How to Create a Generic Method to Get the Enum Description in C#

        public static SelectList GetSelectListForEnumWithDescription(Type enumType)
        {
            var list = new List<Object>();
            Array enumValues = Enum.GetValues(enumType);
         
            foreach (Enum enumValue in enumValues)
            {
                list.Add(new
                              {
                                 ID = (int)Enum.Parse(enumType, enumValue.ToString()),
                                 Value = GetEnumDescription(enumValue)});
                               }
              return new SelectList(list, "ID", "Value");
        }

        public static string GetEnumDescription(Enum value)
        {

            FieldInfo fi = value.GetType().GetField(value.ToString());

            DescriptionAttribute[] attributes =
                (DescriptionAttribute[]) fi.GetCustomAttributes(typeof (DescriptionAttribute), false);

            if (attributes != null && attributes.Length > 0)

                return attributes[0].Description;

            else return value.ToString();
        }
    }

Developer and Reviewer Checklist - Keep Handy while Developing Code

1. Does the code work as expected? 
2. Does the code follow the StyleCop/FxCop/JSLint/SonarLint rules?
3. Review static analysis warning suppressions if any.
4. Do you see any code duplication?
5. Please refer the Portal Standardization sheet as well while implementation
6. Is there any copy-pasted code from any other source?
7. Does the code follow a modular structure?
8. Validate code metrics.
9. Is there any code that is commented out?
10. Are there any TODO markers or any incomplete code?
11. Is proper authentication and authorization in place? Validate across personas
12. Adequate logging (Verbose, Warning, Error etc.)?
13. Does the code handle all exception scenarios?
14. · What happens if call to external system fail?
15. · What happens if the call to database fails?
16. Can the number of database queries be optimized?
17. Proper use of cache?
18. Review transactions
19. Do methods and functions validate inputs before using it?
20. Are comments present and are they appropriate?
21. Do loops have proper terminating conditions?
22. Do methods have too many parameters?
23. Do methods, classes etc. have meaningful names?
24. Does the code perform excessive string concatenation?
25. For custom exception classes, does the code implement the standard exception pattern?
26. For classes that need to implement, do they implement the standard dispose pattern?
27. Does the code use dynamic SQL?
28. Does the code implement guidelines to avoid XSS attack
29. Does the code implement technique to avoid CSRF attack
30. Each UI control should have corresponding ID for automation purpose.
31. For a control type(ex : dropdown), across the pages it should have same control properties.
32. TFS task status update
33. Link TFS ID with check-in
34. Deployment Scripts, RM updated if applicable
35. Verified the successful deployment in Dev integration environment

MetadataException: Unable to load the specified metadata resource in Visual Studio 2012 or in Entity Frame work

When ever you are getting this error , just be sure that this property was bind in you Entity Framework.

Just open your  .edmx file , go to the properties and then set the property of the "Metadata Artifact Processing"  to "Embed in Output Assembly". That's all your problem is fixed.

How to open a new tab On click of a hyper-linked column in Telerik Razor Grid

Today i got a requirement to open a external URL in a tab when the linked column is clicked.
This  can be achieved by simply adding the client template/ template to the linked column.

1) Using Template Attribute in the Telerik Grid

column.Bound(a => a.Website)
      .Template(@<text><a href="@Url.Content(item.Website)" target="_blank">@item.Website</a></text>)
      .HeaderTemplate(
        @<text>
    <a href="javascript:void(0)" class="t-link" orderby="Website">Website</a>
@Html.TextBoxFor(m => m.Filter.Website)         
</text>);

2) Using Client Template Attribute in the Telerik Grid

column.Bound(a => a.Website)
    .ClientTemplate("<a href='<#= Website #>' target='_blank'><#= Website #></a>")
    .HeaderTemplate(
        @<text>
    <a href="javascript:void(0)" class="t-link" orderby="Website">Website</a>
@Html.TextBoxFor(m => m.Filter.Website)         
</text>);

Output:

But the really annoying is that when you click the link it is throwing error  as
 "The resource you are looking for has been removed, had its name changed, or is temporarily unavailable"

This is because the IIS is unable to resolve the path.

Solution to the above issue:

The above issue can be fixed by a simple trick, just you need to append the http:// to the website in the client template or in the template attribute. See the code below:

column.Bound(a => a.Website)
      .Template(@<text><a href="@Url.Content("http://"+item.Website)" target="_blank">@item.Website</a></text>)
      .HeaderTemplate(
        @<text>
    <a href="javascript:void(0)" class="t-link" orderby="Website">Website</a>
@Html.TextBoxFor(m => m.Filter.Website)         
</text>);

Note: Similarly if it is a mail ID column then, use mailto: as the prefix.

Thats it, Enjoy!

How to Add Re-ordering of the columns in Telerik MVC or Razor Grid.

Some times it is required that the column  had to be re-ordered in a grid as, we are using a Telerik grid , as adding the property reorder will do the task.


Here is the code below to do it:

 .Reorderable(reorder => reorder.Columns(true))

  Just add this line to your Telerik Razor grid, it will do the task.

Happy Coding!

How to show the Pager in Telerik Grid both in top and bottom.

While working in a project , my client wants to show the paging in the grid in both in the top of the grid as well as in the bottom of the grid also. As I am using the Telerik grid, it has a property to set while creating the grid. 

So here is the code for it:

.Pageable(p =>
      {
         p.Style(GridPagerStyles.NextPreviousAndNumeric | GridPagerStyles.PageSizeDropDown);    
         p.Position(GridPagerPosition.Both); // this line will do the Magic
         p.PageSize(int.Parse(ViewBag.PageSize ?? "50"), new[] { 10, 20, 50 });
       }).Sortable()

Happy Coding!

How to Insert space before capital letters using Jquery

Assume you have a string "HelloWorld" and you need to show as "Hello World". How you can achieve it using Jquery.

It can be done in a very simpler way as below:

"Your string".replace( /([a-z])([A-Z])/g, "$1 $2")

so here it will be "HelloWorld".replace( /([a-z])([A-Z])/g, "$1 $2") will produce "Hello World"

Enjoy!

Differentiate between 'All' and 'Any' Operators in LINQ.

In LINQ, All operator is  to check whether all the elements met the specific condition or not. While Any operator checks whether there is any element exist in the collection or not.


For Example:

int array={1,2,3,4,5};

bool result=array.All(i=>i < 6); here it will check the elements and returns true.

Similarly,

bool result= array.Any( ); // here it checks whether the collection has any elements and returns true.


Hope you Enjoyed!

Compile Time View Checking In Asp.net MVC

You might have noticed that in MVC3/MVC4 if you had done some thing wrong in the view files it will not throw any error during compilation and it will build successfully. The error in the file is only noticed during executing/rendering the view file. So in order to trap the error during the compilation time you can follow the method below:

Step-1 :
Open your solution project file in any XML Editor or in the Visual Studio itself  and you will find a tag named
<MVCBuildViews>, here it false and just make it true and save it.

<MVCBuildViews>false</MVCBuildViews>  
 change it to 
<MVCBuildViews>true</MVCBuildViews>


Thats all, so now when your view has any error then it will throw error during the compilation.

The Use of ALL Operator in LINQ

Today, I came across the All operator in LINQ. This operator returns bool value rather than records after condition is satisfied. The operator will be highly helpful when you need some kind of validation to find unique data. for e.g. Checking the existing email  or UserID registered and so on.


Lets Go with a Example to do the Task:

int [] array = { 1,2,3,4,5 };

bool result = array.All(value => value > 2 );

Console.WriteLine(result);  // Here it will print False since it will check all the values and                                         // all the values must be grater than 2.


 result = array.All(value => value < 6 );
Console.WriteLine(result); // Here it will print True since it will check all the values and                                          // found all values are less than 6.


Hope it helps you!

Error 349: Duplicate headers received from server in Google Chrome while rendering PDF using ITextSharp in Asp.Net MVC

While working on generating  PDF in Asp.Net MVC3, I got a peculiar error while rendering the PDF in Chrome browsers, which is not being found in any other browsers like Internet Explorer or Fire Fox.

This error comes because chrome browsers doesn't ignore duplicate headers. This can be addressed easily the following ways, if you or your web app is sending out headers. Then check the following things:

 1. Enclose fileName using “”. i.e

Response.Addheader('Content-Disposition: attachment; filename="' + fileName '"');

instead of

Response.Addheader('Content-Disposition: attachment; filename='+ fileName);

2. If possible replace spaces and commas (,) with underscores (_)

 string regExp = @"[^\w\d]";

Response.AddHeader("content-disposition", "attachment;filename=" + "Test_PDF_" + 
                           Regex.Replace(model.CompanyName, regExp, "_")+ "_" +

                              Regex.Replace(model.FullName, regExp, "_") + "_" +                                                         DateTime.Now.ToShortDateString());teString());

3. Explicitly tell Asp.Net MVC to override headers by setting optional replace parameter to true.

Response.AddHeader("Content-type: application/pdf",true);

Happy Coding!

How to prevent the multiple submit of record in ASP.Net MVC using JQuery

There are various methods are available to do that one, it can be done using JQuery, using sessions or Filters.


Method -1 ( Using JQuery Approach)

 $('form').submit(function () {
        if ($(this).find('.input-validation-error').length == 0) {
            $(this).find(':submit').attr('disabled', 'disabled');
        }
    });

This is the simplest method to prevent the multiple submission of the record in MVC and even it works on JQuery Unobstructive validations.

Happy Coding!

How to get a set of record from middle of the table, Say you need records from 5 to 15 from a table containing 100 records in SQL Server

Its a small query that will help you to find the records from from  n to m from a table having N records.

Where N :- total records in the table.
            n :- starting record number.
            m :- ending record number.

select top 20 * from School
except
select top (5) * from School

so, here it first select top 20 records and from it it discards the 1st top 5 records.

Enjoy!

Writing multiple condition for a Kendo Grid column Template to fetch the record.

Sometime you are required to write a template for Kendo Grid to fetch the data on a condition below is the column template to write multiple condition to do it. Its easy one, but to remember those small tricky things, I had posted this one.

Column[

{ field: "DateActivated", title: "Activated", width: 50, 

template: '#=(DateActivated==null)?"":(Status=="Requested")?"":

 kendo.toString(kendo.parseDate(DateActivated"),"MM/dd/yyyy")#',filterable: false }]

Happy Coding!

Getting the Error "The document has no pages" in PDF reporting Using ItextSharp in Asp.net MVC3/MVC4

Today while working with a project, I got a task to do i.e for creating dynamic PDFs of the View.
So I had started working on that and completed before time.

However , when I tried to put into the azure production environment, i got peculiar error which i had not observed in my dev Environment or in the stage.

The error I got is  "The document has no pages" . I started doing research into it but unable to find any solution. At last, I thought that it might be out of memory or buffering issue, no still that is not the case. the problem arises due to inability to find the relative source path that you had provided to the image source in the view while creating the PDF with the logo or images in it.

So, before deploying to the production server be sure the following things has been checked:

1) The Image file which u have used must be existing in the website inside some folder.
2) Be sure that PDF supports few file formats such as .jpg/.bmp, so use the image of that type.
3) Don't use the image source with relative URL, it will not be able to find the image. It will work in the local but throw an error in production or staging server. So better use the live site followed with the image source.


If you are still getting the same error then just try to render some text and check whether it is rendering or not. If it is rendering then there might be some image rendering issue. Is still getting the error then just recheck your code.


Happy coding!

Jquery Method to Check the File upload control Empty or not, File Size and File Type(e.g. JPG,BMP,PDF)

Html:
<input type="file" id="file" name="file" />
<span id="valFile" class=""></span> // span for showing error message.

CSS:


.field-validation-error {
    color: #f00;
}

.field-validation-valid {
    display: none;
}

.input-validation-error {
    border: 1px solid #f00;
    background-color: #fee;
}


JQuery Snippet:
$(document).ready(function( )
{

//Changing the Error message of the File Upload and checking the File size and File type.
        $("#file").change(function () {

            $("#valFile").html("Please select file."); // Default Error Message
         
            var fileExtension = ['jpeg', 'jpg', 'png', 'gif', 'bmp', 'doc', 'docx', 'pdf'];

            if ($(this).val() != "") { //checking wheather the file uploader is empty or not
             
                //Checking the File type
                if ($.inArray($(this).val().split('.').pop().toLowerCase(), fileExtension) == -1) {
                    $(this).addClass("input-validation-error").removeClass("valid");
                    $("#valFile").addClass("field-validation-error").removeClass("field-validation-valid")
                        .html("Invalid Filetype(only image files/doc/docx/pdf)");
                }
                else {
                    $(this).removeClass("input-validation-error").addClass("valid");
                    $("#valFile").removeClass("field-validation-error").addClass("field-validation-valid");

                    if ((this.files[0].size > 4194304) && ($(this).val() != '')) {
                        $(this).addClass("input-validation-error").removeClass("valid");
                        $("#valFile").addClass("field-validation-error").removeClass("field-validation-valid")
                            .html("File size exceeded 4MB");
                    }
                }
            } else {
                $(this).addClass("input-validation-error").removeClass("valid");
                $("#valFile").addClass("field-validation-error").removeClass("field-validation-valid");
            }
        });

});

Happy Coding!

How to create a File Upload with File Validation in Asp.net MVC / How to Use the @Html.TextBoxFor() for File Upload ?

While Wonder how to validate the Upload control in a easy way, I find this solution as the best to do it, although lot of other ways are found.This is because you need not need to write much more code as a normal razor validation will solve the problem.


My View:


 <div id="dvUpload" class="hide fieldControlContainer">
                <div class="innerDivLeft">
                    <label class="blue">Upload Document:</label>
                </div>
                <div class="innerDivRight">
                      @Html.TextBoxFor(model => model.File, new { @class = "inputTextBox", type="file" })
                      @Html.ValidationMessageFor(model => model.File)
                </div>
 </div>

The magic lies with this line  @Html.TextBoxFor(model => model.File, new { @class = "inputTextBox", type="file" }), here it will be rendered as a file upload control rather than a text because we are over riding the default behavior of input tag rendering by specifying it as type="file".

My Controller:



 public ActionResult Index(HttpPostedFileBase file, MyModel model)
        {
                  //Codes written here.
        }


MyModel:

public class MyModel
{

       [Required(ErrorMessage = "Please select file")]     // this is for model validation
        public HttpPostedFileBase File { get; set; }

}

Now your file upload validation will be checked like any other normal control.

How to make a textbox to accept only integers as Input.

Html Page:
 <input type="text" name="age" id="txtAge" />&nbsp;<span id="errormsg"></span>

JQuery Snippet for the above TextBox:

Method-1:
$(document).ready(function () {
  //called when key is pressed in textbox
  $("#txtAge").keypress(function (e) {
     //if the letter is not digit then display error and don't type anything
     if (e.which != 8 && e.which != 0 && (e.which < 48 || e.which > 57)) {
        //display error message
        $("#errormsg").html("Digits Only").show().fadeOut("slow");
               return false;
    }
   });
});

Method-2:
$(document).ready(function () {
    $("#txtAge").keydown(function (e) {
        if (e.shiftKey) e.preventDefault();
        else {
            var nKeyCode = e.keyCode;
            //Ignore Backspace (Keycode=8), Tab keys(Keycode=9)  & Delete(Keycode=46)
         if (nKeyCode == 8 || nKeyCode == 9 || nKeyCode == 46) return;
            if (nKeyCode < 95) {
                if (nKeyCode < 48 || nKeyCode > 57) e.preventDefault();
            } else {
                if (nKeyCode < 96 || nKeyCode > 105) e.preventDefault();
            }
        }
    });
});

Enjoy!

Uploading a file to Server in Asp.net MVC 3 /4.

View page:


@using (Html.BeginForm("Index", "MyController", FormMethod.Post , new { enctype = "multipart/form-data" }))
{
//  Controls for your Model........(see below)

 <div>
                <div class="innerLeftContainer">
                    <label >Full Name:</label>
                </div>
                <div class="innerRightContainer">
                    @Html.TextBoxFor(model => model.FullName, new {@class = "inputTextBox"})
                    @Html.ValidationMessageFor(model=>model.FullName)
                </div>
            </div>


<div id="dvUpload">
                <div class="innerLeftContainer">
                    <label>Upload Document:</label>
                </div>
                    <div class="innerRightContainer">
                        <input type="file" id="DocumentUpload" name="file" />
                    </div>
            </div>


}


Note: The Form Method and the enctype is highly required for uploading your file to the server orthrwise you will always get the HttpPostedFileBase as null.


Action Method: ( in the Controller)
 [HttpPost]
        public ActionResult Index(HttpPostedFileBase file, MyModel model)
        {
            // Verify that the user selected a file
            if (file != null && file.ContentLength > 0)
            {
                // extract only the fielname
                var fileName = Path.GetFileName(file.FileName);
                if (fileName != null)
                {
                    // store the file inside ~/App_Data/uploads folder
                    var path = Path.Combine(Server.MapPath("~/App_Data/uploads"), fileName);
                    file.SaveAs(path);
                }
            }
            // redirect back to the index action to show the form once again
            return RedirectToAction("Index");
        }

Test you Website with different screen resolution and in diferent device

While browsing, today I find out that by providing you website url  below the link helps you to test your site in different resolution.

http://quirktools.com/screenfly/

For Example: I need to test: WWW.Google.com, so give the URL in the textbox. once you give it will activate the devices resolution